Power delivered to load resistor using measured voltage. % difference (Difference divided by expected) You can use Excel to do the calculations to save time filling in the chart. You will only have one load resistor on the circuit at any one time, unused connection points remain unattached!!! To load the circuit you will place one resistor between ground and either Va, Vb or Vc. Do NOT have a load resistor yet on this circuit: It does not need the extra labels that mine has, but make sure the voltage indicators are included and show that you have the correct voltages. Insert the image of your voltage divider circuit here. This will make the 3-D circuit construction easier later.

But to simplify this circuit INSTEAD USE DC POWER SUPPLY FOR 12V SO YOU HAVE A BATTERY ON THE BOARD. To get the 12 V source, can go to Simulate > Instruments >NI ELVIS mx instruments > NI ElVIS Variable Power Supply just like you would see in the ELVIS Instrument panel. This will save you time when you put the load on the circuit, to see the voltage change at the connection point when you add a load. You will want to put voltage indicators on each one connected between ground and each test point. Va, Vb, Vc are the connection points you will use to load to the circuit at 12, 10 and 6V. Part 1: Build a Voltage Divider and Test it with Loads.Ĭonstruct a voltage divider with a 12V source and use 1000, 20 Ohms to divide the voltage into 10V and 6V at nodes in the circuit. YOU WILL LOSE POINTS FOR EVERY CIRCUIT IMAGE THAT DOES NOT HAVE THIS On every Design sheet from the top menu “Place” find “Text” and write your: Later we will see a 3-D Model of the ELVIS Board. You will get a workspace that has the connections you will find on our ELVIS board. START A NEW PROJECT BY GOING TO FILE>NEW>NI ELVIS I Design. Program Files -> National Instruments (folder) -> Circuit Design Suite -> Multisim So I conclude that Multi sim results are wrong, very wrong.Scored out of 10 as part of your Lab Grade. I know Mathematic results are 100% correct, no doubt in that.So I must accept the result which is more closer to the mathematic.So practical results are more near to Multisim results.

The next questions was which results to accept, there are three results This 0.22V error is generated due to various reasons, resistances of wires,not 100% accurate rated capacitors, stray capacitances,and the list goes on and on. Vcc=11.55V approximately equals to 11.77V The results of Computer Simulation on Matlab are like this: The 12V power supply gives around 11.77V when checked by multimeter. I got worried about this thing very much.I performed the same experiment on computer and other practically.I took two real capacitors and and one real multimeter and one breadboard with 12V power supply.

Breadboard in multisim 14.0